Elementary Mathematics II — 2026-exam Past Questions
University of Ilorin MTH102: 113 questions.
Topics: Derivatives as limits of rate of change, differentiation techniques, maxima and minima., Curve sketching, integration, definite integrals, reduction formulae., Applications to areas, volumes (Trapezium and Simpson's rules)., Functions of a real variable, graphs, limits, and continuity.
- If ln y = x, find dy/dx.
- y
- 1/y
- 1
- x²
- The second-derivative condition for a minimum point of a curve (where dy/dx = 0) is:
- dy/dx = 0
- d²y/dx² < 0
- d²y/dx² > 0
- d²y/dx² = 0
- A particle moves so that Y = 20t + (2/3)t³ − (3/2)t² metres. Find its velocity at t = 0 s.
- 0 m/s
- 20 m/s
- −9 m/s
- −1 m/s
- Y = (x − 2)³. Find the stationary (turning) point.
- (−2, 2)
- (−1, 2)
- (3, 3)
- (2, 0)
- Evaluate ∫ x tan⁻¹x dx.
- ((x² + 1)/2) tan⁻¹x − x/2 + C
- (x²/2) tan⁻¹x − x/2 + C
- ((x² − 1)/2) tan⁻¹x + x/2 + C
- (x²/2) tan⁻¹x − ½ ln(1 + x²) + C
- Find the total area enclosed between the curves y = x and y = x³.
- 1/6
- 1/4
- 1/2
- 1/3
- Find the area under the curve y = x³ from x = 1 to x = 2 (that is, between y = 1 and y = 8).
- 35/7
- 15/4
- 45/4
- 11
- If y = cos 3t and x = sin 3t, find dy/dx.
- −tan 3t
- tan 3t
- 3 sin 3t
- −cot 3t
- Evaluate ∫ 3/((x + 1)(2x + 1)) dx
- 3 ln|(2x + 1)/(x + 1)| + C
- 3 ln|(x + 1)/(2x + 1)| + C
- 6 ln|2x + 1| − 3 ln|x + 1| + C
- 3 ln|2x + 1| + 3 ln|x + 1| + C
- If eʸ = x − y, find dy/dx at the point where y = 0.
- 1/2
- 1
- 1/3
- 2
- Find d²y/dx² of y = x eˣ.
- eˣ(x + 2)
- eˣ(x + 1)
- eˣ(x + 3)
- x eˣ
- Differentiate eˣ/x².
- eˣ(x − 2)/x³
- eˣ(2x)/x²
- eˣ(x − 2)/x⁴
- (x eˣ − 2)/x³
- In evaluating ∫ (ln y)/√y dy by parts with u = ln y, find v where dv = dy/√y.
- √y
- 1/(2√y)
- (2/3)√(y³)
- 2√y
- Differentiate with respect to x: y = 10x − 7.
- 10
- −10
- 0
- 3
- Evaluate ∫ (ln x)/x³ dx
- (x²/2)(ln x − 1/2) + C
- (x³/3) ln x + 1/3 + C
- −(1/(2x²))(ln x + 1/2) + C
- −(1/(2x²))(ln x − 1/2) + C
- If y = t² sin t and x = 2t², find dy/dx.
- −cos t
- (1/8)(sin t − t)
- ½ sin t + ¼ + cos t
- (1/4)(2 sin t + t cos t)
- Find the area under the curve y = 3x − x² (above the x-axis).
- 3/2
- −9/2
- 9/5
- 9/2
- Find the area under the curve ∫₁² x³ dx.
- 15/4
- 17/4
- 4
- 8/3
- Find the area enclosed by the curve y = x − 2√x and the x-axis.
- 32/3
- 8/3
- 4/3
- 4
- Differentiate 1/x.
- −1/x²
- −1/(2x)
- x²
- −2/x²
- Find the derivative of y = sin(cos x).
- −sin x cos(cos x)
- cos x sin(cos x)
- −cos x sin(sin x)
- sin x sin(cos x)
- The distance of a particle is x = 20t − (3/2)t² − (2/3)t³ metres. Find its velocity when t = 0.
- 20 m/s
- 15 m/s
- 10 m/s
- 25 m/s
- Find the derivative of (tan⁻¹x)².
- 2 tan⁻¹x/(1 + x²)
- 2 tan⁻¹x
- 2/(1 + x²)
- 1/(1 + x²)²
- Find dy/dz if y = sin(z⁶) + sin⁶z.
- 6z⁵ cos(z⁶) + 6 sin⁵z cos z
- 6z⁵ cos(z⁶) + 6 sin⁵z
- cos(z⁶) + 6 sin⁵z cos z
- 6z⁵ cos(z⁶) − 6 sin⁵z cos z
- Evaluate ∫ 1/(x² − 2) dx
- (1/(2√2)) ln|(x − √2)/(x + √2)| + C
- (1/√2) ln|(x − √2)/(x + √2)| + C
- (1/(2√2)) ln|(x + √2)/(x − √2)| + C
- (1/(2√2)) tan⁻¹(x/√2) + C
- Which rules are suitable for differentiating x² cos x/(x² + 1)?
- Product and Quotient
- Product and Chain
- Quotient and Chain
- Sum and Chain
- Evaluate ∫ 1/√(4 − 9x²) dx
- (1/3) sin⁻¹(3x/2) + C
- (1/3) tan⁻¹(3x/2) + C
- (1/2) sin⁻¹(3x/2) + C
- 3 sin⁻¹(3x/2) + C
- Evaluate ∫ 1/(9 + 16x²) dx
- (1/12) tan⁻¹(4x/3) + C
- (1/3) tan⁻¹(4x/3) + C
- (1/12) sin⁻¹(4x/3) + C
- (1/12) tan⁻¹(3x/4) + C
- The distance of an object is x = 20t − (3/2)t² − (2/3)t³. Find the time t at maximum height.
- 2.5 s
- 4 s
- 5 s
- 2 s
- Evaluate ∫ 1/√(25 − 4x²) dx
- (1/5) sin⁻¹(2x/5) + C
- (1/2) sin⁻¹(2x/5) + C
- (1/2) sin⁻¹(5x/2) + C
- (1/5) tan⁻¹(2x/5) + C
- Differentiate x² ln(2x).
- x(2 ln(2x) + 1)
- 2x ln(2x) + 1
- 2x ln(2x) + x²
- x(ln(2x) + 2)
- Differentiate 1/√(x − 2).
- −1/(2(x − 2)^(3/2))
- 1/(2(x − 2)^(3/2))
- −1/(2√(x − 2))
- −2/(x − 2)^(3/2)
- Evaluate ∫ 2/(x² − 2) dx
- (1/√2) ln|(x − √2)/(x + √2)| + C
- (1/√2) ln|(x + √2)/(x − √2)| + C
- (1/(2√2)) ln|(x − √2)/(x + √2)| + C
- (2/√2) ln|x² − 2| + C
- If x² + y² + 4 = 20, find dy/dx.
- −x/y
- x/y
- −y/x
- −2x/y
- Differentiate tan⁻¹√x.
- 1/(2√x(1 + x))
- 1/(1 + x)
- 1/(2√x)
- √x/(1 + x)
- If x = eᵗ and y = 2 cos 3t, find dy/dx.
- −6 sin 3t/eᵗ
- 6 sin 3t/eᵗ
- −6 cos 3t/eᵗ
- −2 sin 3t/eᵗ
- Evaluate ∫ sin⁻¹x dx
- x sin⁻¹x + √(1 − x²) + C
- x sin⁻¹x − √(1 − x²) + C
- x sin⁻¹x + √(1 + x²) + C
- x sin⁻¹x + 1/√(1 − x²) + C
- Differentiate sin⁻¹(e⁶ᵗ) with respect to t.
- 6e⁶ᵗ/√(1 − e¹²ᵗ)
- e⁶ᵗ/√(1 − e¹²ᵗ)
- 6e⁶ᵗ/(1 − e¹²ᵗ)
- 6e⁶ᵗ/√(1 + e¹²ᵗ)
- Evaluate ∫ (x³ − 3x² − 2/x²) dx
- x⁴/4 − x³ + 2/x + C
- x⁴/4 − x³ − 2/x + C
- 3x² − 6x + C
- x⁴/4 − x³ + 2/x² + C
- Find the derivative of x.
- 1
- 0
- x
- 2
- Evaluate ∫ [ln x]²/x dx
- (ln x)³/3 + C
- (ln x)²/2 + C
- (ln x)³ + C
- 2 ln x/x² + C
- Evaluate ∫₁² x e²ˣ dx
- (3e⁴ − e²)/4
- e²/4
- (3e⁴ + e²)/4
- (e⁴ − e²)/2
- Evaluate ∫₃⁶ (2x² − 5/x²) dx
- 751/6
- 11/3
- 126
- 745/6
- If y = tan⁻¹(5θ), find the differential coefficient dy/dθ at θ = π/180.
- 5/(1 + π²/1296)
- 5/(1 + π²/1256)
- 5/(1 + 25π²)
- 5/(1 + π²/32400)
- Evaluate ∫ (x⁴ + 3x² − 2)(4x³ + 6x) dx
- (x⁴ + 3x² − 2)²/2 + C
- (x⁴ + 3x² − 2)²/4 + C
- (x⁴ + 3x² − 2)³/3 + C
- (x⁴ + 3x²)(x⁴ + 3x² − 2) + C
- If y = 3/(1 − 2x)², find dy/dx.
- 12/(1 − 2x)³
- −12/(1 − 2x)³
- 6/(1 − 2x)³
- 3/(1 − 2x)³
- Evaluate ∫ (6x − 1/(4x²) + 4x − 3) dx
- 5x² − 3x + 1/(4x) + C
- 5x² − 3x − 1/(4x) + C
- 10x² − 3x + C
- 5x² − 3x + 1/(4x²) + C
- If y = (x + 1) sin x, find dy/dx.
- sin x + (x + 1) cos x
- cos x
- sin x − (x + 1) cos x
- (x + 1) cos x
- Find dy/dx if y = x⁴ ln x.
- x³(4 ln x + 1)
- 4x³ ln x
- x³ ln x + 1
- 4x³ + x³ ln x
- Find dy/dx if y = x²/(x + 1).
- x(x + 2)/(x + 1)²
- x(x − 2)/(x + 1)²
- 2x/(x + 1)²
- x²/(x + 1)²
- If x = 3t³ − 2t² + 4t − 1, find the acceleration when t = 1 s.
- 4 m/s²
- 14 m/s²
- 18 m/s²
- 22 m/s²
- Find the turning points of y = x³/3 + x² − 3x + 4.
- (1, 7/3) and (−3, 13)
- (1, 7/3) and (−3, −5)
- (−1, 7/3) and (3, 13)
- (1, 13) and (−3, 7/3)
- If x = 2t − (3/2)t² − (2/3)t³, find the acceleration when t = 0.
- −3 m/s²
- 3 m/s²
- −4 m/s²
- 2 m/s²
- Evaluate ∫ (25 − 4x) dx
- 25x − 2x² + C
- 25x − 4x² + C
- 25 − 2x² + C
- 25x² − 2x + C
- Evaluate ∫ 2x/√(x² + 4) dx
- 2√(x² + 4) + C
- √(x² + 4) + C
- x²/√(x² + 4) + C
- 4√(x² + 4) + C
- Evaluate lim(x→0) (5x² − 2x + 5).
- 5
- 0
- 2
- 10
- Evaluate ∫ 1/(16 + 9x²) dx
- (1/12) tan⁻¹(3x/4) + C
- (1/12) tan⁻¹(4x/3) + C
- (1/4) tan⁻¹(3x/4) + C
- (1/12) sin⁻¹(3x/4) + C
- Evaluate ∫ (sec x tan x)/(sec x + 3) dx
- ln|sec x + 3| + C
- ln|tan x| + C
- sec x + 3 + C
- 1/(sec x + 3) + C
- Evaluate ∫₀^π sin x dx
- 2
- 0
- 1
- −2
- Find dy/dx of y = √(tan 2x).
- sec²2x/√(tan 2x)
- 1/(2√(tan 2x))
- 2 sec²2x √(tan 2x)
- sec 2x tan 2x/√(tan 2x)
- Find dy/dx of x² + xy + y² = 7 at the point (2, 1).
- −5/4
- 5/4
- −4/5
- −3/2
- Find dy/dx of y = e^(3x² + 2x).
- (6x + 2) e^(3x² + 2x)
- e^(3x² + 2x)
- (3x² + 2x) e^(3x² + 2x)
- (6x + 2) e^(6x + 2)
- Find dy/dx of y = csc 2x.
- −2 csc 2x cot 2x
- −csc 2x cot 2x
- 2 csc 2x cot 2x
- −2 csc²2x
- Find dy/dx of y = eˣ/x.
- eˣ(x − 1)/x²
- eˣ/x²
- eˣ(x + 1)/x²
- (eˣ − 1)/x
- Evaluate ∫ x⁴ e^(x⁵) dx
- e^(x⁵)/5 + C
- 5e^(x⁵) + C
- x⁵e^(x⁵)/5 + C
- e^(x⁵)/(5x⁴) + C
- Evaluate ∫₀¹ x²(x³ + 1)² dx
- 7/9
- 1/3
- 7/3
- 8/9
- Evaluate ∫ −x/((2x + 3)(x + 2)) dx
- (3/2) ln|2x + 3| − 2 ln|x + 2| + C
- 3 ln|2x + 3| − 2 ln|x + 2| + C
- (3/2) ln|2x + 3| + 2 ln|x + 2| + C
- −(3/2) ln|2x + 3| + 2 ln|x + 2| + C
- Evaluate ∫ 1/((x + 4)(x − 2)) dx
- (1/6) ln|(x − 2)/(x + 4)| + C
- 6 ln|(x − 2)/(x + 4)| + C
- (1/6) ln|(x + 4)/(x − 2)| + C
- (1/2) ln|(x − 2)/(x + 4)| + C
- Evaluate ∫ 1/(x − 1)² dx
- −1/(x − 1) + C
- 1/(x − 1) + C
- −2/(x − 1)³ + C
- ln|x − 1| + C
- Evaluate ∫ 3x/√(x² + 1) dx
- 3√(x² + 1) + C
- (3/2)√(x² + 1) + C
- 3x²/√(x² + 1) + C
- 6√(x² + 1) + C
- Evaluate ∫ (11 − x)/((x + 4)(x + 1)) dx
- 4 ln|x + 1| − 5 ln|x + 4| + C
- 5 ln|x + 1| − 4 ln|x + 4| + C
- 4 ln|x + 1| + 5 ln|x + 4| + C
- −4 ln|x + 1| + 5 ln|x + 4| + C
- In ∫ x² 3ˣ dx using integration by parts (LIATE), what is u?
- x²
- 3ˣ
- 2x
- x³/3
- Find the second derivative of ln x.
- −1/x²
- 1/x²
- 1/x
- −1/x
- Find the area under the curve y = x^(1/2) between x = 1 and x = 4.
- 14/3
- 7/3
- 16/3
- 2
- Evaluate ∫ dx/(6x² − 7x + 2)
- ln|(3x − 2)/(2x − 1)| + C
- ln|(2x − 1)/(3x − 2)| + C
- 2 ln|2x − 1| − 3 ln|3x − 2| + C
- (1/6) ln|(3x − 2)/(2x − 1)| + C
- What are the values of x at the turning points of y = 4x³ − 3x² − 6x + 1?
- x = 1 and x = −1/2
- x = −1 and x = 1/2
- x = 1 and x = 1/2
- x = −1 and x = −1/2
- Evaluate ∫₁⁴ 1/(x − 2)² dx
- −1/3 (naive value)
- The integral diverges (does not exist)
- 1/3
- 2/3
- Evaluate lim(x→−2) (x² − 7x).
- 18
- −10
- 10
- −18
- Evaluate ∫ (√5 − 2x) dx
- √5 x − x² + C
- √5 − x² + C
- √5 x − 2x² + C
- (√5 x)/2 − x² + C
- Evaluate ∫ 7^(2x + 5) dx
- 7^(2x + 5)/(2 ln 7) + C
- 7^(2x + 5)/ln 7 + C
- 7^(2x + 5)/2 + C
- (2x + 5) 7^(2x + 4) + C
- Evaluate ∫ (4x + 1)³ dx
- (4x + 1)⁴/16 + C
- (4x + 1)⁴/4 + C
- (4x + 1)⁴ + C
- 3(4x + 1)² + C
- In ∫ x³ 3ˣ dx by parts (u = x³, dv = 3ˣ dx), what is v?
- 3ˣ ln 3
- x⁴/4
- 3ˣ/ln 3
- 3x²
- In ∫ x³ 3ˣ dx by parts, what is dv?
- x³
- 3ˣ dx
- 3ˣ
- x³ dx
- Evaluate ∫₂³ 1/√(x − 2) dx
- 2
- 1
- 4
- 1/2
- Differentiate y = x³ ln x.
- x²(3 ln x + 1)
- 3x² ln x
- x³ ln x + 1
- 3x² + x³ ln x
- Evaluate ∫ (3x − 17)/((4x + 1)(3x + 1)) dx
- 18 ln|3x + 1| − (71/4) ln|4x + 1| + C
- 54 ln|3x + 1| − 71 ln|4x + 1| + C
- 18 ln|3x + 1| + (71/4) ln|4x + 1| + C
- (71/4) ln|3x + 1| − 18 ln|4x + 1| + C
- Find dy/dx if x² + 2xy = 7.
- −(x + y)/x
- −(x + y)/(2x)
- (x + y)/x
- −x/(x + y)
- Find dy/dx of y = sin²(3x + π/6) at x = 0.
- π/12
- π/6
- 2√3/3
- 3√3/2
- If y = sin x, find d²y/dx².
- −sin x
- sin x
- cos x
- −cos x
- Evaluate ∫₋₃³ 1/(x² + 9) dx
- π/3
- π/12
- π/6
- π/9
- Find dy/dx if y = (x² + 1)/(x³ + x + 1).
- (−x⁴ − 2x² + 2x − 1)/(x³ + x + 1)²
- (x⁴ + 2x² − 2x + 1)/(x³ + x + 1)²
- (−x⁴ + 2x² + 2x − 1)/(x³ + x + 1)²
- 2x/(3x² + 1)
- Find the derivative of (3x² − 2x)⁴ at x = 1.
- 16
- −48
- 4
- 48
- Evaluate ∫ x sin x dx
- −x cos x + sin x + C
- x cos x − sin x + C
- x sin x + cos x + C
- −x sin x − cos x + C
- Find the area enclosed between the curves y = x² and y = 2x.
- 4/3
- 8/3
- 2/3
- 4
- Evaluate ∫₋₄⁰ (1 − 2x) dx
- 20
- −20
- −12
- 12
- Find the total area enclosed between the curve y = x³ − 2x and the x-axis.
- 2
- 1
- 4
- 0
- Differentiate tan x/x.
- (x sec²x − tan x)/x²
- (sec²x − tan x)/x²
- (x sec²x + tan x)/x²
- sec²x/x
- If dA/dt = t² − 1 and A = 0 when t = 0, find A when t = 1.
- −2/3
- 2/3
- 0
- 1/3
- If f(x) = 15x + 2x² and g(x) = 2x² + x − 3, find f(x) − g(x).
- 14x + 3
- 16x − 3
- 14x − 3
- 4x² + 16x − 3
- Evaluate ∫ x cos x dx
- x sin x + cos x + C
- x sin x − cos x + C
- −x sin x + cos x + C
- x cos x + sin x + C
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