The distance of an object is x = 20t − (3/2)t² − (2/3)t³. Find the time t at maximum height.
University of Ilorin MTH102 2026-exam past question
- 2.5 s
- 4 s
- 5 s
- 2 s
Register free to see the answer and step-by-step explanation
More University of Ilorin MTH102 2026-exam past questions
Related questions
- If ln y = x, find dy/dx.
- The second-derivative condition for a minimum point of a curve (where dy/dx = 0) is:
- A particle moves so that Y = 20t + (2/3)t³ − (3/2)t² metres. Find its velocity at t = 0 s.
- Y = (x − 2)³. Find the stationary (turning) point.
- Evaluate ∫ x tan⁻¹x dx.
- Find the total area enclosed between the curves y = x and y = x³.
