If $y = \frac{m}{m^2+1}$ and $x = m^2+1$, find $\frac{dy}{dx}$.
University of Ilorin MTH102 sodiomatics past question
- $\frac{1-m^2}{2m(m^2+1)^2}$
- $\frac{1+m^2}{2m(m^2+1)^2}$
- $\frac{1-m^2}{m(m^2+1)^2}$
- $\frac{1-m^2}{2m}$
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