Find $\frac{dy}{dx}$ of $y = \tan x + \frac{\sqrt{x+1}}{\sqrt{x}}$.
University of Ilorin MTH102 sodiomatics past question
- $\sec^2 x - \frac{1}{2\sqrt{x^3(x+1)}}$
- $\sec^2 x + \frac{1}{2\sqrt{x(x+1)}}$
- $\sec^2 x - \frac{1}{2\sqrt{x(x+1)}}$
- $\csc^2 x - \frac{1}{2\sqrt{x^3(x+1)}}$
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