Find $\frac{dy}{dx}$ if $y = \ln(x^2 + 3x + 5)$.
University of Ilorin MTH102 sodiomatics past question
- $\frac{2x+3}{x^2+3x+5}$
- $\frac{1}{x^2+3x+5}$
- $\frac{2x}{x^2+3x+5}$
- $\frac{2x+3}{(x^2+3x+5)^2}$
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