Elementary Mathematics II (Calculus) — 2014 Past Questions
Lagos State University MAT102: 50 questions.
Topics: Derivatives as limits of rate of change, differentiation techniques, maxima and minima, Integration, definite integrals, reduction formulae, Applications to areas, volumes (Trapezium and Simpson's rules), Functions of a real variable, graphs, limits, and continuity, Curve sketching, integration, definite integrals, reduction formulae
- The rate of change of the area of a circle with respect to its radius is
- Diameter
- Perimeter
- Area × radius
- 2 × diameter
- Let F(x) = ∫₁ˣ (t³ - 4t² + t + 2) dt. Find F′(4).
- 4
- 5
- 6
- 7
- Compute ∫₄⁹ (1/√t) dt.
- 1
- 2
- 3
- 4
- Evaluate limₙ→∞ (10n² - 3n + 7)/(2n + 6)².
- 1
- 1.5
- 2
- 2.5
- Compute [f(2 + h) - f(2)]/h, where f(x) = 2x² - x + 3.
- 7 - h
- 7 + h
- 7 - 2h
- 7 + 2h
- Compute f′(1) where f(x) = 2√(3x² - 4x + 5).
- 2
- -2
- 1
- 3
- Find the average rate of change of g(t) = t² - 3t + 4 on the interval [2,4].
- 4
- 6
- 8
- 10
- Suppose g(4) = 4, g′(4) = -2, and f(x) = g(x)/x. Find f′(4).
- -5/8
- -7/8
- -3/4
- -5/4
- The second derivative of (x + 4)(11x + 1)(3x - 2) is
- 198x + 226
- 226x² + 198x
- 226x + 198
- 198x² - 226x
- If y = f(x), then at turning points
- f(x) = 0
- dy/dx = 0
- dy/dx > 0
- dy/dx = 1
- Which of these is not correct about the first principle?
- dy/dx = [f(x+h) - f(x)]/x
- dy/dx = [f(x-h) + f(x)]/h
- dy/dx = lim_{h→0} {[f(x+h) - f(x)]/h}
- dy/dx = lim_{x→0} {[f(x+h) - f(x)]/x}
- What is the limit of (x³ - 1)/(x² - 1) as x → 1?
- ∞
- -∞
- 3/2
- 1
- Evaluate lim_{x→π/2} (sin x)/(cos x).
- Not possible
- π/2
- 0
- ∞
- If y = 112, then dy/dx is
- 112
- 112y
- 112x
- 211
- If f(x,y) = 1 + x²/y + y³/x, calculate f(20,14).
- 5837/35
- 20378/35
- 697/7
- 10009/5
- Given g(x) = 2 + 3x - 8x² and h(x) = (x - 1)², then g(h(x)) is
- Very difficult
- 3 + 26x - 45x² - 8x⁴
- -3 + 26x - 45x² + 32x³ - 8x⁴
- 3 - 26x - 45x² - 32x³ - 8x⁴
- At minimum points of y = f(x), which of the following is correct?
- d²y/dx² = 1
- d²y/dx² < 0
- d²y/dx² = 0
- d²y/dx² > 0
- The equation y = x³(x - 4) has ______ number of inflexion.
- 1
- 2
- 3
- 4
- If y = θⁿ, where n ∈ ℤ⁺, which of the following is not correct?
- θ²y″ - n²y′ + ny = 0
- θy′ = ny
- θ²y″ = n(n-1)y
- y + y′ = nθⁿ(n⁻¹ + θ⁻¹)
- Differentiate sin²(x² + 1).
- 4x cos²(x² + 1)
- 2 cos(x² + 1)
- 4x sin(x² + 1) cos(x² + 1)
- 2x sin²(x² + 1) cos(x² + 1) + 2x
- The first derivative of cosᵐ ψ with respect to ψ is
- -m cosᵐ⁻¹ ψ sin ψ
- m cosᵐ⁻¹ ψ sinᵐ ψ
- -m sinᵐ⁻¹ ψ cosᵐ ψ
- m sinᵐ ψ
- Find d/dx [arcsin((1 - x²)/(1 + x²))].
- Not possible
- 2(1 + x²)
- (1 - x²)/(1 + x²)
- -2/(1 + x²)
- The demand and cost functions of Cyntax Nig. Ltd are p = 22500 - 3q², C = 5000 + 14400q. The marginal revenue function is
- 22500 - 3q²
- -6q
- 22500² - 3q³
- 22500 - 9q²
- The quantity for maximum revenue is
- 49
- 50
- 51
- 52
- The price for maximum revenue is
- 13000
- 14500
- 15000
- 13500
- The profit function is
- 5000 - 8100q + 3q³
- 8100q - 3q³ + 5000
- -8100q - 5000 + 3q³
- 8100q - 5000 - 3q³
- The marginal profit function is
- 8100 - 9q²
- -8100 + 9q²
- 8100 + 9q²
- -8100 - 9q²
- The maximum profit is
- 175000
- 150070
- 157000
- 751000
- The price for maximum profit is
- 19800
- 8100
- 5000
- 22500
- The average cost function is
- 5000q + 14400q²
- 14400q
- 5000q⁻¹ + 14400q²
- 5000q + 7200q²
- The marginal cost function is
- 5000
- 14400
- q² + 1
- 5000q - q²
- At what quantity is the marginal cost a minimum?
- 0
- Any quantity
- 50
- 28
- Find the equation of the tangent at the point (2,2) on the curve y² = 2x.
- x - 2y + 2 = 0
- y - 2x - 2 = 0
- x - 2y - 2 = 0
- y + 2x - 2 = 0
- The equation of the normal at the point (3, 4/3) on xy = 4 is
- 12x - 27y - 65 = 0
- 27x + 12y + 65 = 0
- 12x + 27y + 65 = 0
- 27x - 12y - 65 = 0
- The minimum value of y = x³ - 3x² - 9x + 27 is
- 54
- 0
- 27
- -27
- The maximum value of y = x³ - 3x² - 9x + 27 is
- 36
- 34
- 32
- 30
- The integral ∫ (5x + 3)^0.5 dx evaluates to
- (5x + 3)^1.5/1.5
- (3/2)(5x + 3)^(-0.5)
- (3/10)(5x + 3)^0.5
- (2/15)(5x + 3)^1.5
- ∫₂^{2√3} dx/(x² + 4) =
- π/4
- 1/2 arctan(1/2 x)
- π/3 - π/4
- π/4 - π/3
- The best substitution to evaluate ∫ x√(a² - x²) dx is
- x = a cos θ
- x = a sin θ
- u = a² - x²
- x = a tan θ
- Evaluate ∫₀² √(x/(4 - x)) dx.
- π + 2
- 2 - π
- π - 2
- 2
- Integrate cos² ax with respect to x.
- cot ax + c
- tan² ax + c
- (1/a)cot ax + c
- (-1/a)cot ax + c
- Evaluate ∫ ln x dx.
- Not Possible
- ln x + c
- ln x - x + c
- x ln x - x + c
- The expression for ∫ x e^{3x} dx is
- (1/3)x e^{3x} - (1/9)e^{3x} + c
- (1/3)e^{3x} - (1/9)x e^{3x} + c
- (1/3)x e^{3x} + (1/9)e^{3x} + c
- (-1/3)e^{3x} + (1/9)x e^{3x} + c
- A rule f which assigns to each element x of a set X a unique element y of a set Y is called
- Equation
- Differential
- Function
- Integration
- If y(x) = u(x)v(x)w(x), then dy/dx is
- uvw + uvw + uvw
- does not exist
- uvw + uvw + uvw
- uvw + uvw
- Given that the acceleration of an electron is y = ∫ e^{cos x} ln x arcsin x dx, then the velocity of this electron is
- e^{sin x} ln x arccos x
- ln x sin x
- e^{cos x} e^x
- e^{cos x} ln x arcsin x
- Evaluate ∫_a^a e^{sin x} ln x arccos x dx.
- 0
- 1
- 2
- 2a
- Evaluate ∫ dx/(x ln x).
- ln x + c
- ln(x ln x) + c
- ln(ln x) + c
- x ln x + c
- Integrate x with respect to x.
- -x + c
- x²/2 + c
- x + c
- 1 + c
- Using the substitution u = t - 1/t, the integral ∫ (t² + 1)/(t⁴ + 1) dt reduces to
- ∫ du/(u² + 1)
- ∫ du/(u² + 2)
- ∫ du/(u² + 3)
- ∫ du/(u² + 4)
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