If $f(x) = \frac{4x}{2x^2 - 1}$, find $f'(x)$.
University of Ilorin MTH102 2023 past question
- $\frac{-8x^2 - 4}{(2x^2 - 1)^2}$
- $\frac{8x^2 - 4}{(2x^2 - 1)^2}$
- $\frac{8x^2 + 4}{(2x^2 - 1)^2}$
- $\frac{-8x^2 + 4}{(2x^2 - 1)^2}$
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