If $f(x) = \\frac{4x}{2x^2 - 1}$, find $\\frac{dy}{dx}$.
University of Ilorin MTH102 integral past question
- $\\frac{-8x^2 - 4}{(2x^2 - 1)^2}$
- $\\frac{8x^2 - 4}{(2x^2 - 1)^2}$
- $\\frac{8x^2 + 4}{(2x^2 - 1)^2}$
- $\\frac{-8x^2 + 4}{(2x^2 - 1)^2}$
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