Given that $\\sin\\alpha = \\frac{2}{3}$ and $\\cos\\beta = \\frac{1}{2}$, find $\\sin(\\alpha + \\beta)$.
University of Ilorin MTH101 ester past question
- $\\frac{2 + \\sqrt{15}}{6}$
- $\\frac{2 - \\sqrt{15}}{6}$
- $\\frac{1 + \\sqrt{5}}{3}$
- $\\frac{1 - \\sqrt{5}}{3}$
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