Given $\\sin \\alpha = \\frac{2}{3}$ and $\\cos \\beta = \\frac{1}{2}$, find $\\sin(\\alpha + \\beta)$.
University of Ilorin MTH101 ester past question
- $\\frac{2 + \\sqrt{15}}{6}$
- $\\frac{2 + \\sqrt{10}}{6}$
- $\\frac{2 + \\sqrt{5}}{6}$
- $\\frac{2 + \\sqrt{3}}{6}$
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