Given E°(Zn²⁺/Zn) = -0.25V, E°(Cu²⁺/Cu) = +0.34V, the cathode is:

University of Ilorin CHM101 2022 past question

  1. Zn
  2. Cu
  3. H₂
  4. Pt

Register free to see the answer and step-by-step explanation

More University of Ilorin CHM101 2022 past questions

Related questions

SmartDriller logo

SmartDriller

Loading your past questions, mock exams, notes, and video tutorials...

Starting up…