Calculate the number of moles of KMnO₄ that are present in 15.8g of KMnO₄? (K = 39.0, Mn = 54.9, O = 16.0)
University of Ilorin CHM101 2015 past question
- 0.10 mole
- 0.02 mole
- 0.20 mole
- 0.05 mole
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