Calculate the electrical energy and power used by an electric heater of 11 Ω when the voltage source is 220 V AC for 2 seconds. (Duplicate of Q11, but with wording 'electrical charge and power'? Actually Q34: 'Calculate the electrical charge and power'? Let's see: 'Calculate the electrical charge and power used by an electric heater of 11Ω when the voltage source is 220V AC for 2 seconds.' They ask for charge and power, but energy? Possibly they mean energy and power. Charge would be Q = I*t, but that's not typical for a heater. I'll assume they mean energy and power, as in Q11. Given options same as Q11. So same answer: 8.8 kJ, 4.4 kW.
University of Ilorin PHY102 2025A past question
- 4.4 kJ, 8.8 kW
- 8.8 kJ, 4.4 kW
- 2.2 kJ, 8.2 kW
- 8.5 kJ, 4.4 kW
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