Calculate ΔH at 298.15K for the reaction: 2Na(s) + 2H₂O(l) → 2NaOH(s) + H₂(g). Given ΔH°f[H₂O(l)] = -285.8 kJ/mol and ΔH°f[NaOH(s)] = -426.8 kJ/mol.
University of Ilorin CHM101 2020 past question
- -291.9 kJ
- -281.9 kJ
- -271.9 kJ
- +281.9 kJ
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