A particle moves with constant acceleration a = (2i - 3j) m/s². At t = 0, it is at position r₀ = (5i + 2j) m with velocity v₀ = (4i + 6j) m/s. Find its position and velocity at t = 3.0 s.
University of Ilorin PHY101 2026-exam past question
- r = (26i + 6.5j) m; v = (10i - 3j) m/s
- r = (17i + 20j) m; v = (10i - 3j) m/s
- r = (26i + 6.5j) m; v = (10i + 15j) m/s
- r = (31i - 2.5j) m; v = (6i + 6j) m/s
Register free to see the answer and step-by-step explanation
More University of Ilorin PHY101 2026-exam past questions
Related questions
- A car's suspension consists of springs with an overall effective spring constant of 120 kN/m. How much would you have to compress the sprin…
- An object rotates with angular momentum L. What will happen to its angular velocity if its moment of inertia is doubled?
- A 3.00 kg particle has a velocity of (3.0i - 4.0j) m/s. Find the magnitude of its total momentum.
- An object A is moving with 5 m/s and object B is moving with 20 m/s in the same direction (positive x-axis). Find the velocity of B with re…
- A man climbs a mountain with an amount of energy E. The energy he gains when descending the mountain is equal to:
- When a box is dragged on the floor, the work done on the box in the form of potential energy is:
